ANGLE SUM PROPERTY: HOW TO DESCRIBE ITS OF TRIANGLE – (2024)

INTRODUCTION:

A plane figure formed by three line segments that are non-parallel to each other is called the triangle.(ANGLE SUM PROPERTY)

ANGLE SUM PROPERTY: HOW TO DESCRIBE ITS OF TRIANGLE – (1)

If A,B,C are three non-collinear points in the plane of the paper, then the figure made up by the three line segments AB, BC and CA is called a triangle with vertices A,B,C. The triangle contains three vertices A,B and C and three non-parallel line segments AB,BC and CA. This triangle is denoted by ΔABC. AB, BC and CA are sides of ΔABC. Three angles are ˂BAC, <ABC and <ACB.

ELEMENTS or PARTS: The three sides are AB, BC, CA and three angles <A, <B, <C of ΔABC are together called the six parts or elements of ΔABC.

INTERIOR and EXTERIOR of TRIANGLE: We observe that all points in the plane ΔABC are divided into following three parts:

ANGLE SUM PROPERTY: HOW TO DESCRIBE ITS OF TRIANGLE – (2)

  • INTERIOR: The part made up by all such points P which are enclosed by ΔABC is called the interior of ΔABC.
  • EXTERIOR: The part made up by all such point Q which are not enclosed by ΔABC is called the exterior of ΔABC.
  • TRIANGULAR REGION: The interior of ΔABC itself includes P and R is called the triangular region ΔABC.

TYPES OF TRIANGLES

  • Naming of triangles by considering the lengths of their sides:-
  • Scalene Triangle:

ANGLE SUM PROPERTY: HOW TO DESCRIBE ITS OF TRIANGLE – (3)

A triangle whose no two sides are equal is called a scalene triangle. ΔABC is a scalene triangle.

  • Isosceles Triangle:

ANGLE SUM PROPERTY: HOW TO DESCRIBE ITS OF TRIANGLE – (4)

A triangle whose two sides are equal is called an isosceles triangle. ΔABC is an isosceles triangle so AB = AC.

  • Equilateral Triangle:

A triangle whose all sides are equal to one another, is called an equilateral triangle. ΔABC is an equilateral triangle where AB = AC = BC.

  • Naming triangles by considering the measures of their angles:-
  • Acute Triangle :

ANGLE SUM PROPERTY: HOW TO DESCRIBE ITS OF TRIANGLE – (5)

A triangle whose all the angles are acute is called an acute angled triangle or an acute triangle.

ΔABC is an acute-angled triangle where <A, <B and < C are acute angles. Equilateral triangle is an acute-angled triangle because the measure of its each angle is 60°.

  • Right Triangle:

ANGLE SUM PROPERTY: HOW TO DESCRIBE ITS OF TRIANGLE – (6)

A triangle whose one angle is a right angle, is called right-angled triangle or a right triangle.

The side opposite to the right triangle is known as hypotenuse and other two sides are called the legs of the triangles.

ΔABC is a right-angled triangle, where <B = 90° remaining two angles are acute.

  • Obtuse triangle:

ANGLE SUM PROPERTY: HOW TO DESCRIBE ITS OF TRIANGLE – (7)

A triangle whose one angle is obtuse, is called an obtuse-angled triangle or an obtuse triangle, where <E is an obtuse angle.

ANGLE SUM PROPERTY OF A TRIANGLE

PROPERTY: The sum of the angles of a triangle is two right angles or 180°

ANGLE SUM PROPERTY: HOW TO DESCRIBE ITS OF TRIANGLE – (8)

PROOF: Let ΔABC be any triangle. Through A, a line XY parallel to the side BC . Since, XY||BC and the and the transversal AB cuts XY and BC at A and B respectively.

<1 = <4 [ as alternate interior angles are equal ]

Similarly , XY ||BC and the transversal AC cuts XY and BC at A and C respectively.

<2 = <5 [ as alternate interior angles are equal]

Also <3 = <3

Adding the angles on the respective sides, we get

<1 + <2 + <3 = <4 + <5 + <3

But, <4 + <5 + <3 = 180° = 2 right angles.

Hence, the sum of the angles of a triangle is two right angles or 180°.

From the above property, we obtain the following useful results:-

A triangle cannot have more than one right angle.

A triangle cannot have more than one obtuse angle i.e if one angle of the triangle is obtuse, then other two are acute.

In a right triangle, the other two angles are always acute and their sum is 90°.

EXTERIOR ANGLE PROPERTY OF A TRIANGLE

PROPERTY: When a side of a triangle is produced then the exterior angle so formed is equal to the sum of its interior opposite angle.

ANGLE SUM PROPERTY: HOW TO DESCRIBE ITS OF TRIANGLE – (9)

To prove, in ΔABC, BC has been produced to point D, forming an exterior angle <ACD.

To prove : <ACD = <CAB + < ABC

CONSTRUCTION: from C, CE is drawn which parallel to BA.

PROOF: Since CE||BA and AC is transversal.

So we have <ACE = < CAB [ alternate angle]

Again, CE ||BA and BCD is a transverse

So, <ECD = <ABC [corresponding angle]

Adding the corresponding sides

<ACE + <ECD = <CAB + <ABC

<ACD = <CAB + < ABC

Therefore, it is proved that exterior angle of a triangle is always equal to the sum of its interior opposite angle.

Let’s discuss some problem on the angle sum property of triangle:

Problem 1: Two angles of a triangle measures 63° and 47° respectively. Find the measure of the third angle of the triangle.

Solution: Let the measure of the third angle be x°; since the sum of all the three angles of a triangle is 180°, we have

63 + 47 + x = 180

Or, 110 + x = 180

Or, x = 180 – 110 = 70

Therefore, the measure of the third angle is 70°

Problem 2: The angles of a triangle are in the ratio 2: 3: 4, find the measure of each angle of the triangle.

Solution: Let the measures of the given angles be 2x° , 3x° , 4x°,

Since the sum of the angles of a triangle is 180°, so we have : 2x + 3x + 4x = 180

Or, 9x = 180

Or, x = 180/9 = 20

Angles are : 2 X 20 = 40

3 X 20 = 60

4 X 20 = 80

Therefore, the measures of three angles are 40° , 60° , 80°.

Problem 3: Calculate the value of x in the downward figure. ( what is angle sum property of a triangle)

ANGLE SUM PROPERTY: HOW TO DESCRIBE ITS OF TRIANGLE – (10)

Solution: In ΔABC, we have:

<BAC + <ABC + <BCA = 180°

Or, 40°+ <ABC + 90 = 180°

Or, <ABC + 130° = 180°

Or, <ABC = 180 – 130 = 50°

IN ΔBDE , we have:

<EBD + <BDE + < DEB = 180°

Or, <ABC + <BDE + < DEB = 180°

Or, 50° + x° + 100° = 180°

Or, x° + 150°= 180°

Or, x° = 180 – 150 = 30°

Therefore, the value of x = <DEB = 30°.

Problem 4 : Calculate the value of x in the downward figure.

ANGLE SUM PROPERTY: HOW TO DESCRIBE ITS OF TRIANGLE – (11)

Solution: AD is joined to produce to E.

Since the exterior angle of a triangle is equal to the sum of interior opposite angles, so

In ΔACD, <CDE = <DCA + <CAD…………………………(i)

In ΔABD, < EDB = <DAB + <ABD………………………….(ii)

Adding (i) and (ii) , we have;

<CDE + <EDB = <DCA + <CAD + <DAB + <ABD

Or, x° = 30° + (<CAD + <DAB) + 45°

Or, x° = 30° + 55° + 45° = 130°

Or, x° = 130°

Therefore, the value of x = 130°.

Problem 5: In a right triangle, one of the acute angles is 58°. Find the other acute angle.

Solution: Let the measure of the other acute angle be x°, then the angles of the triangle are 90°, 58° and x° .

Since sum of all three angles of triangle is 180◦ according to the angle sum property,

So, 90° + 58° + x° = 180°

Or, 148° + x° = 180°

Or, x = 180 – 148

Or, x = 32°

Therefore, the measure of the other acute angle is 32°.

Problem 6: In the adjoining figure ΔABC is right-angled at <C, and CD ḻ AB , also <A = 65°. Find (i) ACD ; (ii) <BCD; (iii) <CBD.

ANGLE SUM PROPERTY: HOW TO DESCRIBE ITS OF TRIANGLE – (12)

Solution: ΔABC is right-angled triangle,

<C = 90°

<A = 65°

So, <B = 180° – (90° + 65°)

Or, <B = 180 – 155 = 25°

Or, <CBD = 25°

As, CD ḻ AB, Therefore, <ADC = <CDB = 90°

In, ΔACD, we have,

<ACD + <CAD + <ADC = 180°

Or, <ACD + 65°+ 90° = 180°

Or, <ACD = 180 – (90 +65) = 25°

In ΔBCD, we have,

<BCD + <CBD + <BDC = 180°

Or, <BCD + 25° + 90° = 180°

Or, <BCD = 180 – ( 90 + 25) = 65°

Therefore, <ACD = 25° , <BCD = 65° , <CBD = 25°.

Problem 7: In ΔABC, D,E are points on sides AB and AC in such a way that DE||BC. If <B = 30° and <A = 40°, find x°,y°, z°. ( what is angle sum property of a triangle)

ANGLE SUM PROPERTY: HOW TO DESCRIBE ITS OF TRIANGLE – (13)

Solution: In ΔABC, we have,

<A = 40° and <B = 30°

So, <A + <B + <C = 180°

Or, 40°+ 30° + <C = 180°

Or, <C = 180° – (40° +30°)

Or, <C = 110°

DE||BC and transversal AB cuts them at E and c respectively.

<ACB = <AED ……………………. (corresponding angles)

So, y° = z° = 110°

Again, DE||BC and transversal AB cuts them at D and B respectively.

<B = <ADE ………………………….(corresponding angles)

x° = 30°

Therefore, x° = 30° ; y° = 110° ; z° =110°.

Problem 8: This figure has been obtained by using two triangles. Find out <A+<B+<C+<D+<E+<F

ANGLE SUM PROPERTY: HOW TO DESCRIBE ITS OF TRIANGLE – (14)

Solution: We know that the sum of the angles of a triangle is 180°

In ΔACE, we have <A +<C+<E = 180°……………..(i)

In ΔBDF, we have <B+<D+<F = 180°………………(ii)

Adding the corresponding sides of (i) and (ii)

We get : <A+<C+<E+<B+<D+<F= 180° + 180°,

So, <A+<B+<C+<D+<E+<F = 360°

Therefore, sum of the six angles are 360°.

Problem 9 : Calculate the value of of x.

ANGLE SUM PROPERTY: HOW TO DESCRIBE ITS OF TRIANGLE – (15)

Solution: DBC is a straight line, we have:

<ABD + <ABC = 180°

<ABC = 180 – (<ABD) = 180 – 138 = 42°.

BC = AC = < BAC = <ABC = 42°.

In ΔABC, we have;

<BAC +<ABC +<BCA = 180°

Or, 42° + 42° + x° = 180°

Or, 84° + x° = 180°

Or, x° = 180 – 84 = 96°

Therefore, value of x = 96°

Problem 10: Calculate the value of x. (what is angle sum property of a triangle)

ANGLE SUM PROPERTY: HOW TO DESCRIBE ITS OF TRIANGLE – (16)

Solution: AB = AC ; so, <ACB = <ABC ………(angles opposite to equal sides of a triangle are equal)

Now, in ΔABC, we have;

<BAC + <ABC +<ACB = 180°

Or, 90°+ 2<ABC = 180°

Or, 2<ABC = 180 – 90

So, <ABC = <BCA = 45°

AC = CD

<CAD = <ADC = x°

Since, exterior angle of a triangle is equal to the sum of interior opposite angles,

So we have <ACB = <CAD +<ADC = 45°……..( <ACB = x° + x° )

2x° = 45°

Or, x° = (221/2

Therefore, the value of x = (221/2)°.

ANGLE SUM PROPERTY: HOW TO DESCRIBE ITS OF TRIANGLE – (2024)

References

Top Articles
Latest Posts
Article information

Author: Prof. Nancy Dach

Last Updated:

Views: 5756

Rating: 4.7 / 5 (57 voted)

Reviews: 80% of readers found this page helpful

Author information

Name: Prof. Nancy Dach

Birthday: 1993-08-23

Address: 569 Waelchi Ports, South Blainebury, LA 11589

Phone: +9958996486049

Job: Sales Manager

Hobby: Web surfing, Scuba diving, Mountaineering, Writing, Sailing, Dance, Blacksmithing

Introduction: My name is Prof. Nancy Dach, I am a lively, joyous, courageous, lovely, tender, charming, open person who loves writing and wants to share my knowledge and understanding with you.